[darksmoke]

PHP код:

foreach($_POST['check'] as $ID)

        {

             $result = mysql_query("select from `books` where `ID`='$ID'");

        //удаляем записи

             while ($row = mysql_fetch_array($result)) { 

             unlink($del.$row['Path']);

             $sql_books_del = mysql_query("delete from `books` where `ID`='$ID'");

             echo "Книга удалена.";

             }

        } 

пишет: Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in Z:\home\allbooks\www\books_delete.php on line 28

строка 28: $result = mysql_query("select from `books` where `ID`='$ID'");