1. пытался опросить модем в kppp, если ставить /dev/ttyUSB0 то сообщение:
error opening modem device !
если ставить /dev/usb/ttyACM0 - программа зависает на сообщении: Looking for modem, а в терминал пишет:
ASSERT: "strlen(LOCK_DIR)+strlen(device) < MaxPathLen" in opener.cpp (205)
Minicom выдет примерно тоже:
minicom: не могу открыть /dev/usb/ttyACM0: Invalid argument
2. Дистрибутив ALT Master 2.2
wvdialconf /etc/wvdial.conf
Scanning your serial ports for a modem.
ttyS0<*1>: ATQ0 V1 E1 -- failed with 2400 baud, next try: 4800 baud
ttyS0<*1>: ATQ0 V1 E1 -- failed with 4800 baud, next try: 9600 baud
ttyS0<*1>: ATQ0 V1 E1 -- failed with 9600 baud, next try: 19200 baud
ttyS0<*1>: ATQ0 V1 E1 -- failed with 19200 baud, next try: 115200 baud
ttyS0<*1>: ATQ0 V1 E1 -- and failed too at 115200, giving up.
ttyS1<*1>: ATQ0 V1 E1 -- failed with 2400 baud, next try: 4800 baud
ttyS1<*1>: ATQ0 V1 E1 -- failed with 4800 baud, next try: 9600 baud
ttyS1<*1>: ATQ0 V1 E1 -- failed with 9600 baud, next try: 19200 baud
ttyS1<*1>: ATQ0 V1 E1 -- failed with 19200 baud, next try: 115200 baud
ttyS1<*1>: ATQ0 V1 E1 -- and failed too at 115200, giving up.
Port Scan<*1>: S2 S3 S4 S5 S6 S7 S8 S9
Port Scan<*1>: S10 S11 S12 S13 S14 S15 S16 S17
Port Scan<*1>: S18 S19 S20 S21 S22 S23 S24 S25
Port Scan<*1>: S26 S27 S28 S29 S30 S31 SA0 SA1
Port Scan<*1>: SA2 SC0 SC1 SC2 SC3 SI0 SI1 SI2
Port Scan<*1>: SI3 SI4 SI5 SI6 SI7 SI8 SI9 SI10
Port Scan<*1>: SI11 SI12 SI13 SI14 SI15 SL0 SR0 SR1
Port Scan<*1>: SR2 SR3 SR4 SR5 SR6 SR7 SR8 SR9
Port Scan<*1>: SR10 SR11 SR12 SR13 SR14 SR15 SR16 SR17
Port Scan<*1>: SR18 SR19 SR20 SR21 SR22 SR23 SR24 SR25
Port Scan<*1>: SR26 SR27 SR28 SR29 SR30 SR31 SR256 SR257
Port Scan<*1>: SR258 SR259 SR260 SR261 SR262 SR263 SR264 SR265
Port Scan<*1>: SR266 SR267 SR268 SR269 SR270 SR271 SR272 SR273
Port Scan<*1>: SR274 SR275 SR276 SR277 SR278 SR279 SR280 SR281
Port Scan<*1>: SR282 SR283 SR284 SR285 SR286 SR287 USB0 USB1
Port Scan<*1>: USB2 USB3 USB4 USB5 USB6 USB7 USB8 USB9
Port Scan<*1>: USB10 USB11 USB12 USB13 USB14 USB15
и тишина