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Цитата:
у меня не получалось так сделать
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получается
Код: 
echo vcbParam1-cParam1 >> log.txt
copy \\dc01\Olimpiada\aParam1 \\vcbParam1-cParam1\c$\ >> log.txt
echo vcbParam1-cParam2 >> log.txt
copy \\dc01\Olimpiada\aParam1 \\vcbParam1-cParam2\c$\ >> log.txt
echo vcbParam1-cParam3 >> log.txt
copy \\dc01\Olimpiada\aParam1 \\vcbParam1-cParam3\c$\ >> log.txt
echo vcbParam2-cParam1 >> log.txt
copy \\dc01\Olimpiada\aParam1 \\vcbParam2-cParam1\c$\ >> log.txt
echo vcbParam2-cParam2 >> log.txt
copy \\dc01\Olimpiada\aParam1 \\vcbParam2-cParam2\c$\ >> log.txt
echo vcbParam2-cParam3 >> log.txt
copy \\dc01\Olimpiada\aParam1 \\vcbParam2-cParam3\c$\ >> log.txt
echo vcbParam3-cParam1 >> log.txt
copy \\dc01\Olimpiada\aParam1 \\vcbParam3-cParam1\c$\ >> log.txt
echo vcbParam3-cParam2 >> log.txt
copy \\dc01\Olimpiada\aParam1 \\vcbParam3-cParam2\c$\ >> log.txt
echo vcbParam3-cParam3 >> log.txt
copy \\dc01\Olimpiada\aParam1 \\vcbParam3-cParam3\c$\ >> log.txt
echo vcbParam1-cParam1 >> log.txt
copy \\dc01\Olimpiada\aParam2 \\vcbParam1-cParam1\c$\ >> log.txt
echo vcbParam1-cParam2 >> log.txt
copy \\dc01\Olimpiada\aParam2 \\vcbParam1-cParam2\c$\ >> log.txt
echo vcbParam1-cParam3 >> log.txt
copy \\dc01\Olimpiada\aParam2 \\vcbParam1-cParam3\c$\ >> log.txt
echo vcbParam2-cParam1 >> log.txt
copy \\dc01\Olimpiada\aParam2 \\vcbParam2-cParam1\c$\ >> log.txt
echo vcbParam2-cParam2 >> log.txt
copy \\dc01\Olimpiada\aParam2 \\vcbParam2-cParam2\c$\ >> log.txt
echo vcbParam2-cParam3 >> log.txt
copy \\dc01\Olimpiada\aParam2 \\vcbParam2-cParam3\c$\ >> log.txt
echo vcbParam3-cParam1 >> log.txt
copy \\dc01\Olimpiada\aParam2 \\vcbParam3-cParam1\c$\ >> log.txt
echo vcbParam3-cParam2 >> log.txt
copy \\dc01\Olimpiada\aParam2 \\vcbParam3-cParam2\c$\ >> log.txt
echo vcbParam3-cParam3 >> log.txt
copy \\dc01\Olimpiada\aParam2 \\vcbParam3-cParam3\c$\ >> log.txt
echo vcbParam1-cParam1 >> log.txt
copy \\dc01\Olimpiada\aParam3 \\vcbParam1-cParam1\c$\ >> log.txt
echo vcbParam1-cParam2 >> log.txt
copy \\dc01\Olimpiada\aParam3 \\vcbParam1-cParam2\c$\ >> log.txt
echo vcbParam1-cParam3 >> log.txt
copy \\dc01\Olimpiada\aParam3 \\vcbParam1-cParam3\c$\ >> log.txt
echo vcbParam2-cParam1 >> log.txt
copy \\dc01\Olimpiada\aParam3 \\vcbParam2-cParam1\c$\ >> log.txt
echo vcbParam2-cParam2 >> log.txt
copy \\dc01\Olimpiada\aParam3 \\vcbParam2-cParam2\c$\ >> log.txt
echo vcbParam2-cParam3 >> log.txt
copy \\dc01\Olimpiada\aParam3 \\vcbParam2-cParam3\c$\ >> log.txt
echo vcbParam3-cParam1 >> log.txt
copy \\dc01\Olimpiada\aParam3 \\vcbParam3-cParam1\c$\ >> log.txt
echo vcbParam3-cParam2 >> log.txt
copy \\dc01\Olimpiada\aParam3 \\vcbParam3-cParam2\c$\ >> log.txt
echo vcbParam3-cParam3 >> log.txt
copy \\dc01\Olimpiada\aParam3 \\vcbParam3-cParam3\c$\ >> log.txt
Цитата FOR /?:
FOR /L %переменная IN (начало,шаг,конец) DO команда [параметры]
Набор раскрывается в последовательность чисел с заданными началом, концом
и шагом приращения. Так, набор (1,1,5) раскрывается в (1 2 3 4 5),
а набор (5,-1,1) заменяется на (5 4 3 2 1)
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Отправлено: 20:19, 14-12-2012
| #4
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